Implement JSON Parse polyfill in JavaScript
Explore the code implementation of JSON Parse Polyfill in JavaScript that can parse a string into valid JSON.
Anuj Sharma
Last Updated Jun 15, 2026

The JSON.parse() method in JavaScript is used to parse a JSON string and transform it into a JavaScript object. However, for older browsers that do not support this method, a polyfill can be implemented to provide this functionality.
Code Implementation: JSON Parse Polyfill
In the case of JSON.parse(), if a browser does not support this method, we can create a polyfill that mimics its behavior to ensure consistent functionality across different browsers. There are 3 appraoches to implement the polyfill of JSON parse.
Approach1: Code Implementation using eval()
Let's take a look at a simple implementation of a polyfill for JSON.parse():
if (!window.JSON) {
window.JSON = {
parse: function(jsonString) {
return eval('(' + jsonString + ')');
}
};
}
In the code snippet above, we first check if the JSON object is available in the global scope. If not, we create a new object with a parse method that uses eval() to parse the JSON string.
It is important to note that using eval() can be risky due to security concerns, as it evaluates JavaScript code. In a production environment, it is recommended not to use eval().
Approach 2: JSON Parse Polyfill Implementation using safe eval()
A safer approach to implementing the JSON Parse polyfill is to use a more robust method such as JSON.parse() itself if available or a custom parsing function. Here is an enhanced version of the polyfill:
if (!window.JSON) {
window.JSON = {
parse: function(jsonString) {
if (/^[\],:{}\s]*$/.test(jsonString.replace(/\\["\\\/bfnrtu]/g, '@').
replace(/(?:^|:|,)(?:\s*\[)+/g, ''))) {
return eval('(' + jsonString + ')');
}
throw new SyntaxError('Invalid JSON');
}
};
}
In this version, we perform additional checks on the JSON string to ensure its validity before using eval(). This helps prevent potential security vulnerabilities that may arise from parsing untrusted input.
Testing the Polyfill
Let's test our polyfill implementation with a sample JSON string:
var jsonString = '{"name": "John", "age": 30}';
var parsedObject = JSON.parse(jsonString);
console.log(parsedObject);
When you run this code, it should output the parsed JavaScript object:
{ name: 'John', age: 30 }
Approach 3: Parsing each type in a recursive call
We'll create a recursive parser that:
- Reads the input string.
- Maintains a current index.
- Detects value type.
- Recursively parses nested arrays and objects.
- Returns the final JavaScript value.
if (!JSON.myParse) {
JSON.myParse = function (jsonString) {
let index = 0;
function skipWhitespace() {
while (/\s/.test(jsonString[index])) {
index++;
}
}
function parseString() {
index++;
let result = "";
while (
index < jsonString.length &&
jsonString[index] !== '"'
) {
result += jsonString[index];
index++;
}
index++;
return result;
}
function parseNumber() {
let start = index;
while (
/[0-9.\-]/.test(jsonString[index])
) {
index++;
}
return Number(
jsonString.slice(start, index)
);
}
function parseTrue() {
index += 4;
return true;
}
function parseFalse() {
index += 5;
return false;
}
function parseNull() {
index += 4;
return null;
}
function parseArray() {
index++;
const result = [];
skipWhitespace();
while (jsonString[index] !== "]") {
result.push(parseValue());
skipWhitespace();
if (jsonString[index] === ",") {
index++;
}
skipWhitespace();
}
index++;
return result;
}
function parseObject() {
index++;
const result = {};
skipWhitespace();
while (jsonString[index] !== "}") {
const key = parseString();
skipWhitespace();
index++;
const value = parseValue();
result[key] = value;
skipWhitespace();
if (jsonString[index] === ",") {
index++;
}
skipWhitespace();
}
index++;
return result;
}
function parseValue() {
skipWhitespace();
const char = jsonString[index];
if (char === '"') return parseString();
if (char === "{") return parseObject();
if (char === "[") return parseArray();
if (char === "t") return parseTrue();
if (char === "f") return parseFalse();
if (char === "n") return parseNull();
return parseNumber();
}
return parseValue();
};
}
In conclusion, implementing a JSON Parse polyfill in JavaScript allows developers to ensure consistent behavior across different browsers, especially in older environments that lack native support for JSON.parse(). While the polyfill provided here offers a basic implementation, it is important to consider security implications and opt for safer alternatives in production code.
Further Reading
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